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a6aab6fa2d
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5faed85cf1
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@ -1,15 +1 @@
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# Ignore all executables
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### Ignore all
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*
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### Unignore all with extensions
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!*.*
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### Unignore all dirs
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!*/
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# Regular gitignore
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.direnv
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# Haskell IR files
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*.hi
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*.o
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@ -2,7 +2,6 @@
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"cSpell.words": [
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"concat",
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"coprime",
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"elems",
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"foldl"
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]
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}
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15
flake.nix
15
flake.nix
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@ -55,18 +55,6 @@
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Chart-cairo
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]
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);
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clean = pkgs.writeShellScriptBin "clean" ''
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# Delete executables
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find . -type f -executable -not -path '*/.git/*' -delete
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# Delete all Haskell IR files
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find . -type f -name '*.hi' -delete
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find . -type f -name '*.o' -delete
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# Delete any test graphs created
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find . -type f -name 'test.png' -delete
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'';
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in
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pkgs.mkShell {
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buildInputs = with pkgs.haskellPackages; [
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@ -75,9 +63,6 @@
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haskell-language-server
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ghcid
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hlint
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# Scripts
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clean
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];
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shellHook = ''
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@ -1,49 +0,0 @@
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import qualified Data.List as List
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import qualified Data.Maybe as Maybe
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import Data.Set (Set)
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import qualified Data.Set as Set
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{-
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interviewing.io question:
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<https://interviewing.io/mocks/linked-in-python-matching-pairs>
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Given a list of whole positive numbers, how would you go about finding two numbers in that list that sum up to a given target number. Assume no duplicates in list.
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-}
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wholePositiveNumbers :: Set Integer
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wholePositiveNumbers = Set.fromAscList [1..1_000_000]
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-- findTargetSumIn xs n =
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-- (if abs (x-n) `member` xs
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-- && abs (x-n) + x == n
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-- then Just (abs (x-n), x)
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-- else Nothing) : findTargetSumIn xs n
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-- where
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-- x =
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ans lst sum = List.nubBy isMirror $ Maybe.catMaybes $ Set.elems $ Set.map (\x ->
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let x' = abs (x-sum)
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in
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if x' `Set.member` lst
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&& x' + x == sum
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then Just (x',x)
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else Nothing
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) lst
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isMirror (a,a') (b,b')
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= a == b'
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&& b == a'
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example = Set.fromList [14,13,6,7,8,10,1,2]
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example' = Set.fromList [14,13,6,7,8,10,1]
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example'' = Set.fromList [1,14,13,3,6,7,2,8,10,4]
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main = do
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print "Quick 3 answers:"
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print $ ans example 3
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print $ ans example' 3
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print $ ans example'' 5
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print "Long answer"
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print $ ans wholePositiveNumbers 3
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@ -221,6 +221,4 @@ ans :: [Integer]
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ans = take 10 $ reverse . digits $ sum oneHundredFiftyDigitNumbers
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main :: IO ()
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main = do
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print ans
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print (sum oneHundredFiftyDigitNumbers)
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main = print ans
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@ -63,5 +63,3 @@ test = map (filter . multipleOf) [1..10]
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-- lol
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solve = foldl1 lcm [1..20]
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main = print solve
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@ -13,29 +13,16 @@ Find the difference between the sum of the squares
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of the first one hundred natural numbers
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and the square of the sum.
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-}
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upperRange :: Integer
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upperRange = 1_000_000
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square :: Num a => a -> a
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upperRange = 100
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square n = n^2
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squares :: [Integer]
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squares = map square [1..upperRange]
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sum' :: [Integer] -> Integer
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sum' = go 0
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where
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go acc [] = acc
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go acc (x:xs) = go (acc+x) xs
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sumOfSquares :: Integer
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sumOfSquares = sum squares
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sumOfSquares = sum' squares
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squareOfTheSum :: Integer
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squareOfTheSum = sum [1..upperRange] ^2
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squareOfTheSum = (sum [1..upperRange])^2
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solution :: Integer
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solution = squareOfTheSum - sumOfSquares
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main :: IO ()
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main = print solution
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@ -1,9 +1,6 @@
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-- https://projecteuler.net/problem=7
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-- Find the 10_001 prime number
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-- import Data.Numbers.Primes (primes)
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import Math.NumberTheory.Primes (primes)
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primes1 :: [Integer]
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primes1 = 2:3:prs
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where
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primes3 = sieve [2..]
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where
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sieve (p : xs) = p : sieve [x | x <- xs, x `mod` p > 0]
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main :: IO ()
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main = print $ "Arithmoi - Math.NumberTheory.Primes: " <> show ans
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ans = primes !! 10_000_000
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@ -28,7 +28,6 @@ What is the value of this product?
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module Main where
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import Data.Char (ord)
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import Data.Foldable (maximumBy)
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import Data.List (sort)
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import Data.List.Split (splitOn)
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@ -47,16 +46,9 @@ digits = go []
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main :: IO ()
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main = print ans
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ans :: ([Integer], Integer)
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ans = (l, p)
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where
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l = maximumBy c $ (windowsOf 13 . digits) thousandDigitNum
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p = product l
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c a b
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| product a > product b = GT
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| product a < product b = LT
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| otherwise = EQ
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-- "([5,5,7,6,6,8,9,6,6,4,8,9,5],23514624000)"
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ans :: [[Integer]]
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ans = (windowsOf 13 . digits) thousandDigitNum
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-- "9878799272442"
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-- what dose it mean to have the greatest product in adjacent digits?
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-- why ask it like that???
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@ -17,39 +17,14 @@ Find the product `abc`.
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-}
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main :: IO ()
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main = do
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print answer
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print (product answer)
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main = print answer
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-- head $ [(a,b,c) | a <- [1..limit], b <- [a+1..limit], c <- [limit - a - b], a < b, b < c, a^2 + b^2 == c^2]
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answer :: [Integer]
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answer = head $
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[ [a, b, c] |
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a <- [1 .. limit],
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b <- [a + 1 .. limit],
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c <- [limit - a - b],
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b < c,
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a ^ 2 + b ^ 2 == c ^ 2]
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where limit = 1000
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limit = 1000
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version1 = [ [a, b, c] |
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a <- [1 .. limit],
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b <- [a + 1 .. limit],
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c <- [limit - a - b],
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b < c,
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a ^ 2 + b ^ 2 == c ^ 2]
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version2 = [ [a, b, c] |
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a <- [1 .. limit],
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b <- [a + 1 .. limit],
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c <- [limit - a - b],
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b < c,
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a ^ 2 + b ^ 2 == c ^ 2]
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answer :: String
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answer = "I dunno"
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solve :: Integer -> [(Integer, Integer, Integer)]
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solve x = takeWhile (\(a,b,c) -> a + b + c == 1000) $ primitiveTriplesUnder x
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solve x = takeWhile (\(a,b,c) -> a + b + c <= 1000) $ primitiveTriplesUnder x
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euclid'sFormula :: Num c => (c, c) -> (c, c, c)
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euclid'sFormula (m, n) = (a,b,c)
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, b < c
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]
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{-
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{-
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- Solution to Project Euler problem 9
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- Copyright (c) Project Nayuki. All rights reserved.
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-
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-
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- https://www.nayuki.io/page/project-euler-solutions
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- https://github.com/nayuki/Project-Euler-solutions
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-}
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-- -- Computers are fast, so we can implement a brute-force search to directly solve the problem.
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-- perim = 1000
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-- main = putStrLn (show ans)
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-- ans = head [a * b * (perim - a - b) | a <- [1..perim], b <- [a+1..perim], isIntegerRightTriangle a b]
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-- isIntegerRightTriangle a b = a < b && b < c
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-- && a * a + b * b == c * c
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-- where c = perim - a - b
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-- Computers are fast, so we can implement a brute-force search to directly solve the problem.
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perim = 1000
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main = putStrLn (show ans)
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ans = head [a * b * (perim - a - b) | a <- [1..perim], b <- [a+1..perim], isIntegerRightTriangle a b]
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isIntegerRightTriangle a b = a < b && b < c
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&& a * a + b * b == c * c
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where c = perim - a - b
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